Question

evaluate without using trigonometric table : tan 12° tan 38° tan 52° tan 60° tan 78°​

Answer 1

Answer:

it is the Table

Step-by-step explanation:

Good luck

Answer 2

tan 12° tan 38° tan 52° tan 60° tan 78°​ $\Rightarrow \sqrt{3}$

Step-by-step explanation:

Given: tan 12° tan 38° tan 52° tan 60° tan 78°​

Formula: $\tan\theta=\cot(90^\circ-\theta)$

$\tan\theta=\dfrac{1}{\cot\theta}$

$\Rightarrow \tan12^\circ\times \tan38^\circ\times \tan52^\circ\times \tan60^\circ\times \tan78^\circ$

$\Rightarrow \cot(90-12^\circ)\times \cot(90-38^\circ)\times \tan52^\circ\times \tan60^\circ\times \tan78^\circ$

$\Rightarrow \cot78^\circ\times \cot52^\circ\times \tan52^\circ\times \tan60^\circ\times \tan78^\circ$

$\Rightarrow \dfrac{1}{\tan78^\circ}\times \dfrac{1}{\tan52^\circ}\times \tan52^\circ\times \tan60^\circ\times \tan78^\circ$

$\Rightarrow 1\times 1\times \sqrt{3}$

$\Rightarrow \sqrt{3}$

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