Evaluate: x^0/64^2/3
Answers
Answered by
1
Step-by-step explanation:
0
64
{x
1/3
}dx
=∫
0
64
(x
1/3
−[x
1/3
])dx
=∫
0
64
x
1/3
dx−∫
0
64
[x
1/3
]dx
=
4/3
x
4/3
∣
0
64
−[∫
0
1
0dx+∫
1
8
1dx+∫
8
27
2dx+∫
27
64
3dx]
=
4/3
4
4
−[0+(8−1)+2(27−8)+3(64−27)]
=3.4
3
−[7+38+111]
=192−7−38−111
=36
hope helpful!?
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