evaluate- x×x + 7x + 12
Answers
Answered by
4
Answer:
×*x+3x+4×+12=0
x(x+3)+4(×+3)=0
(×+4)(×+3)=0
×+4=0 or ×+3=0
×=-4ot ×=-3
Answered by
1
Step-by-step explanation:
x²-7x+12
➜x²-3x-4x+12
➜x(x-3)+-4(x-3)
➜(x-3)(x-4)
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