Question

Evaluate x³-3x²y+3xy²-y³
find the value, of x= -2 , y= -3

Please Answer it quickly...​

Answer 1

Answer:

1

Step-by-step explanation:

x³-3x²y+3xy²-y³

at x= -2 , y= -3

value of polynomial=(-2) ³-3×(-2)²(-3)+3(-2)(-3)²-(-3)³

= -8+36 -54+27

= 63 - 62

= 1

so value of the polynomial= 1

Answer 2

Answer:

-2cube-3(-2sqare-3)+3(-2-3sqare)+3cube

-8-21-33+27

-29-33+27

-62+27-35