Question

Find the altitude and area of an issules triangle
when Dinimites is 32 cm and whose base is 12cm​

Answer 1

Correct question :-

Find the altitude and area of an isosceles triangle. when Diameter is 32 cm and whose base is 12cm.

Answer :-

• Altitude of the ∆ is 8cm.
• Area of the ∆ is 42cm².

Given :-

• Diameter of the triangle = 32cm.
• Base of the triangle = 12cm.

To find :-

• The altitude of the triangle.
• The area of the triangle.

Solution :-

We know that,

• Two sides of the triangle are equal in an isosceles triangle.

Let the two sides be x

12 + x + x = 32

➢ 12 + 2x = 32

• Transpose 12 to other side.

➢ 2x = 32 - 12

• Subtract.

➢ 2x = 20

• Transpose 2 to other side.

➢ x = $\bf \dfrac{20}{2}$

➢ x = 10cm.

Now, Let's find the height of the ∆.

➢ 10² = h² + 6²

➢ 100 = h² + 36

➢ h = √100 - 36

➢ h = √64

➢ h = 8cm.

Hence, Height/altitude of the ∆ is 8cm.

Now, Let's find the area of the ∆.

Area of a triangle = 0.5 × b × h

➢ 0.5 × 12 × 8

➢ 6 × 8

➢ 42 cm².

Hence, The area of the ∆ is 42 cm².

Answer 2

Answer:

area of a triangle

1/2(12)32

1/2(384)

192