Evaluate x³+y³-3x²y+3xy² for x=2 and y=-2
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Answered by
2
Answer:
48
Step-by-step explanation:
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Answered by
2
Answer:
1
Step-by-step explanation:
x³-3x²y+3xy²-y³ at x= -2 , y= -3value of polynomial=(-2) ³-3×(-2)²(-3)+3(-2)(-3)²-(-3)³ = -8+36 -54+27= 63 ...
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