Math, asked by tanishq20, 1 year ago

Evaluate x3 + y3 + z3-3xyz when x =-2 ,y= -1 and z= 3.

Anonymous: As x+y+z = 0 , x³+y³+z³ = 3xyz

Anonymous: 3(-2)(-1)(3) = 18

Anonymous: So , 3xyz-3xyz = 0

Light1729: yeah

Light1729: exactly that was what i was Telling them

Answers

Answered by MarathaKT

-8+(-1)+27-3*-2*-1*3= -9+27-18= 27-27= 0

MdFaiz11: this condition hasn't given there

Light1729: See again, x=-2, y=-1 and z=3

Light1729: x+y+z=0

Anonymous: Yep , @Light1729

MarathaKT: condition needed to be specifically mentioned in the question... we cant asume conditions bro

Light1729: its not an assumption

Light1729: its what is given, we just have to observe

MdFaiz11: stop your typing

Anonymous: It's not worth explaining... @Light1729

Light1729: okay! @TheRevenant

Answered by MdFaiz11

I hope you will be satisfied

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