Math, asked by tanishq20, 1 year ago

Evaluate x3 + y3 + z3-3xyz when x =-2 ,y= -1 and z= 3.


Anonymous: As x+y+z = 0 , x³+y³+z³ = 3xyz
Anonymous: 3(-2)(-1)(3) = 18
Anonymous: So , 3xyz-3xyz = 0
Light1729: yeah
Light1729: exactly that was what i was Telling them

Answers

Answered by MarathaKT
12
-8+(-1)+27-3*-2*-1*3= -9+27-18= 27-27= 0

MdFaiz11: this condition hasn't given there
Light1729: See again, x=-2, y=-1 and z=3
Light1729: x+y+z=0
Anonymous: Yep , @Light1729
MarathaKT: condition needed to be specifically mentioned in the question... we cant asume conditions bro
Light1729: its not an assumption
Light1729: its what is given, we just have to observe
MdFaiz11: stop your typing
Anonymous: It's not worth explaining... @Light1729
Light1729: okay! @TheRevenant
Answered by MdFaiz11
30
I hope you will be satisfied
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