Question

evaluate :x4-x3+x2-x+1for x =2

Answer 1

Hey friend, ☺️ here is your answer ____________________________

${x}^{4} - {x}^{3} + {x}^{2} - x + 1 \\ x = 2 \\ = {2}^{4} - {2}^{3} + {2}^{2} - 2 + 1 \\ = 16 - 8 + 4 - 2 + 1 \\ = 21 - 10 \\ = 11$
Hope this helps you...

Answer 2

Hey friend✋! here is your answer

______________________________
✅To evaluate-{x^4-x^3+x^2-x+1)

✔️x=2

✅Put x=2 in given equation

⭕️so,

✅(2)^4-(2)^3+(2)^2-2+1

✔️16-8+4-2+1


✅21-10

✅11

________________________

⭐️Hope it helps you⭐️

#Rohan ( Maths aryabhatta)♥️