evalute 11/sigma/k=1 (2+3)k
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2
22 upon( 5 k (k+1)) ithink is the answer
Answered by
0
Answer
K=1
∑
11
(2+3
K
)
=
K=1
∑
11
2+
K=1
∑
11
3
K
=11×2+
(3−1)
(3)(3
11
−1)
=22+
2
3
(3
11
−1)
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