Evalute cot.12 38.cot 52.cot 60.cot 78
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Answer:
1/√3
Step-by-step explanation:
we know
cot(90-X)=tanX
so, cot12=tan78
cot38=tan52
The question becomes
tan78*cot78*tan52*cot*52*cot60
Now, tanX*cotX=1, so,
the question simplifies to cot60
now cot60=1/√3
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