evalute (i) (3²+4²)½ (ii) (1²+2³+3³)½
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Answered by
5
1. (3+4)^1/2x2
=7^1
=7
2. =(1+8+27)^1/2
=36^1/2
=(6)^2x1/2
= 6^1 =6
hope it helps
=7^1
=7
2. =(1+8+27)^1/2
=36^1/2
=(6)^2x1/2
= 6^1 =6
hope it helps
Answered by
1
(3^2+4^2)^1/2
=(3^2)^1/2 +(4^2)^1/2
=3^1 + 4^1
=3+4
=7
(1²+2³+3³)½
= (1+8+27)^1/2
= (36)^1/2
= (6^2)^1/2
= 6^1
= 6
=(3^2)^1/2 +(4^2)^1/2
=3^1 + 4^1
=3+4
=7
(1²+2³+3³)½
= (1+8+27)^1/2
= (36)^1/2
= (6^2)^1/2
= 6^1
= 6
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