Question

Evalute i^×(j^×k^) and j^×(k^×i^)​

Answer 1

Answer:

$\huge\underline{\overline {\mid {\bold{\red{ληsωεя}}\mid}}}$

εяяσя σηє

Answer 2

the formula for cross product of vector is given as

mod a * mod b * sin theta

if a and b are vector given and theta is angle betw them.

j^x k^= = 1 k^ (1 is mag, k is directon as angle betw them is 90° so sin theta is 1

similarly

i vector x k vector is -1j vector ans of 1st

k vector x i vector= 1j vector

j vector x vector= 0 { since theta is 0° and sin 0 is 0}

hope it helps

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