Question

evalute the following algebraic expressions
x²+y²-z²-3xyz if x=1,z=2​

Answer 1

Answer:

X=1,z=2

1²+y²-2²-3(1)(y)(2)

1+y²-4-6y

y²-6y-3

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

RHS:

= (x+y+z)×(x²+y²+z²–xy–yz–zx)

= x³ + xy² + xz² – x²y – xyz – zx² + yx² + y³ + yz² – xy² – y²z – xyz + zx² + zy² + z³ – xyz – yz² – z²x

= x³+y³+z³–3xyz

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