Question

Evalute the following where a=2 and b= -1
b^2×a^2×2ab×a^2b/4

Answer 1

B^2 × a^2 = (ba)^2 = (-1×2)^2 = (-2)^2 = 4

2ab × a^2b/4 = ab × a^2b)/2 = a^3 b^2/2 = (-1)^2 (2)^3/2
= 4× 1 = 4

So 4×4 = 16

Answer 2

as according to the question

a = 2, b = -1 (given)

so by putting values of 'a' and 'b' in the equation we get :-

(-1)^2 X (2)^2 X 2(2)(-1) X (2)^2(-1)/4

= 1 X 4 X -4 X -1

= 16

Hope it Helps You!!!

:-)