Question

evalute the valiue of b^2+3b+9 when b=2

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Answer 1

As per the data given in the question,

We have to determine the value of given expression i.e. $b^2+3b +9$ when the value of $b =2$

So, for calculating the value of given expression,

We need to put the value of "b" in the given expression.

So, putting the value of "b" in above expression,

We will get,

$b^2+3b +9\\=>2^2+(3\times 2)+9\\=>4+6+9\\=>19$

Hence, the value of given expression i.e. $b^2+3b +9$ when the value of $b =2$ will be 19.

Answer 2

Given: The equation$b^{2} +3b+9$, and$b=2$.

We have to evaluate the value of$b^{2} +3b+9$.

For this, we will put the value of $b=2$in the given equation.

and then we will get the value of the given equation.

We have$b=2$.

Now,

=> $b^{2} +3b+9$

$=>2^{2} +3\times2+9\\=>4+6+9\\=>19.$

We get $b^{2} +3b+9$$=19 when b=2$

Hence, the value of$b^{2} +3b+9$ when $b=2$will be$19$.