Question

evalute( xpower4-ypower4)(xpower4+ypower4)​

Answer 1

Answer:

x8-y8

Step-by-step explanation:

using identity (x-y)(x+y)= x2-y2

(x4)2-(y4)2

x8-y8

Answer 2

Answer:

Step-by-step explanation:

    x6 – y6 = (x2)3 – (y2)3 = (x2 – y2)[(x2)2 + x2y2 +(y2)2], by (3)

                       = (x + y)(x – y)(x4 + x2y2 + y4),                    by (1)

 

(b)        x6 – y6 = (x3)2 – (y3)2 = (x3 + y3)(x3 – y3),                  by (1)

                        = (x + y)(x2 – xy + y2)(x - y)(x2 +xy +y2),      by (2) and (3)

 

Which of the above factorization is correct?

 

Of course, (b) is the complete factorization, (a) is not.

 

Comparing the results in (a) and (b), we can get:

 

           x4 + x2y2 + y4 = (x2 + xy + y2)(x2 –xy + y2)