Question

evalute (z2+4)(z2-1/4)​

Answer 1

Answer:

$z^4 - \dfrac{z^2}{4} + 4z^2 - 1$

Step-by-step explanation:

$\implies( z^2 + 4 ) ( z^2 - \dfrac{1}{4} )\\\\\implies ( z^4 - \dfrac{z^2}{4} + 4z^2 - 1 )$

Some Extra Points:

• This is a polynomial with degree 4. Therefore it is called as bi-quadratic equation.
• Solution for this equation can be 0, 1, 2, 3 or 4.

Hope it helps !!

Have a great day :)

Answer 2

Solutions:

(z2+4)(z²-1/4)

(z²-z²/4 + 4z² - 1)

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