Question

Evaluvate:(sin2 15°+sin2 75°)+√3(tan 13°.tan 60°.tan 27°.cot 20°.cot 70°.tan 77°.tan 63°)​

Answer 1

Answer:

I will be using the identities:

sin²x = cos²(90-x)

sin²x + cos²x = 1

cot(x) = tan(90-x)

tan(x) * cot(x) = 1

(sin²15° + sin²75°) + √3(tan13°•tan77°)•(tan27°•tan63°•)(cot20°•cot70°)(tan60°)

= (sin²15 + cos²15) + √3(tan13•cot13)(cot20•tan20)(tan60°)

= 1 + √3(1) (1) (tan60°)

= 1 + √3 (tan60°) =

1 + √3(√3/2) = 1 + 3/2 = 5/2

Answer 2

Answer:

t e r a k a t g a y a l o v d e o k k s a m ja