Math, asked by NitinNischal1, 1 year ago

evalvuate : integral^π\2 to 0 dx/1+cosx

Answers

Answered by tarun0001

1

Change 1+ cosx = 2cos2x
Integration of 1/4sec2x = 1/2tan2x/2 =1/4tan2x
Applying limit 1/4tanpi - 1/4tan0

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