Question

Evaulate the integral from 0 to pi/6 of sin3x

Answer 1

π0sin3xdx. now ddx(cos3x)=−3sin3x. ∴∫π 0sin3xdx=[−13cos3x]π0. =−13{[cos3x]π−[cos3 x]0}. =−13(cos3π−cos0). =−13(−1−1).

Answer 2

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