Question

Every year the population increases by 8%.If the present population is 13905, what was the population a year ago

Answer 1

Step-by-step explanation:

ATQ

(100 +8)%=13,905

108%=13,905

1%=13,905/108

100%= 13,905/108 ×100

100%=12,875

Answer 2

Let the  population of the town an year ago be = x

The present population of the town be  =  x + 8/100... (as 8% of the population increases annually)

and the present population = 54000

so ,

108x/100 = 54000

x = 50000...

Cross check

50000* 8/100 = 4000 (8% increase in population) 

 

50000- 4000 = 4600 population the previous year.