Physics, asked by prasoonjha18, 7 months ago

Everyone of you would know if we throw any body from a greater height it would gain a greater force (If not you can verify it by Sir Isaac Newton's 3rd law of motion, i.e. it bounces more if we throw it from a greater height) but according to the equation "F=ma", it shouldn't as neither the mass is increasing nor the acceleration is increasing but if we take another equation "F=(p1-p2)/t", it should gain more force as the because of the increasing velocity, rate of change is momentum is higher and we know the rate of change of momentum is equal to the force. But NCERT has shown us that these two equations are mathematically the same thing. Can you tell me what mistake am I doing?

Answers

Answered by hazydaze
2

Answer:

Acceleration changes with change in height.

Explanation:

In higher classes you will learn that magnitude of acceleration due to gravity at different points on earth is not the same and varies with height of depth as g=G×M/(R)². The acceleration due to gravity is maximum at the earth's surface and decreases either we go at higher altitudes or we move below the surface.

Moreover,as the air drag being applied on the concerned body increases,it reduces the downward acceleration with which the body is moving. Usually while studying classical physics we ignore air drag or any other resistance.

Answered by Anonymous
4

Answer:

The rate law or rate equation for a chemical reaction is an equation that links the reaction rate with the concentrations or pressures of the reactants and constant parameters (normally rate coefficients and partial reaction orders). For many reactions the rate is given by a power law such as.

taht was the mistake u wre doing

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Explanation:

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