Question

everyone please solve it
A(-5,4),B(-2,2),C(3,-2)​

Answer 1

Step-by-step explanation:

Here, A(5,4),B(−3,−2) and C(1,−8) and AD is median.

∴ D is the midpoint of BC

∴D=(

2

−3+1

,

2

−2(−8)

)

=(−1,−5)

and equation of A(5, 4) and D(−1,−5) is

x−5

y−4

=

5−(−1)

4−(−5)

=

6

9

=

2

3

2y−8=3x−15

∴3x−2y−7=0 is the equation of median AD.

Now, Slope of AC=

5−1

4−(−8)

=

4

12

=3

The required line is parallel to AC and passes through B(−3,−2).

So, equation of required line is

y−(−2)=3[x−(−3)]

y+2=3x+9

y=3x+7

Hence, 3x−y+7=0 is the required equation of line.

Answer 2

Answer:

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