Question

Ex. (1) The perimeter of a rectangle is 40 cm. The length of the rectangle is
more than double its breadth by 2. Find length and breadth.​

Answer 1

Answer

• Length of rectangle = 14 cm.

• Breadth of rectangle = 6 cm.

Given

• Perimeter of the rectangle = 40cm.

• Length of the rectangle is more than double it's breadth by 2.

To Find

• Length and breadth of the rectangle.

Step By Step Explanation

Given that ⤵

• Perimeter of the rectangle = 40 cm.

• Length of rectangle is more than double it's breadth by 2.

Let us consider length be 2 + 2x and breadth be x.

$\dag\boxed{\tt{\green{Perimeter_{(Rectangle)} = 2(Length + Breadth)}}}$

By substituting the values

$:\implies\sf40 = 2(2 + 2x + x) \\ \\ :\implies\sf40 = 2(2 + 3x) \\ \\:\implies\sf 40 = 4 + 6x \\ \\ :\implies\sf40 - 4 = 6x \\ \\ :\implies\sf \cancel\cfrac{36}{6} = x \\ \\:\implies\bf 6 = x$

Therefore, length = 2x + 2 => 14 cm. and breadth = x => 6 cm.

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Answer 2

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Given:-

• perimeter of rectangle=40cm
• length is 2 more than double it's breadth

To find:-

• Length and breadth

Solution:-

Formula for perimeter= 2(L+B)

now permeter is given

• 40cm=2(L+B)

• 40cm=2(2B+2+B)

• 40cm=4+6B

• B=6cm. L=2B+2=14cm

Length=14cm

breadth=6cm