Question

Ex. 41. The solubility product of chalk is 9.3 x 10^-8. Calculate its solubility in grams per litre.​

Answer 1

Answer:

Solubility in gram/litre = 0.0304 gram/litre

Answer 2

Given,

The solubility product of chalk = 9.3 × $10^{-8}$

To find,

Solubility of chalk in gram per litre.

Solution,

In order to solve the question quickly and easily we can follow the given steps.

From what knowledge, we have of this chapter in Chemistry we know that,

The chemical equation for the formation of chalk is

$CaCO_{3}$ ⇄ $Ca^{2+}+CO{3} ^{2-}$

Now, we are going to let the solubility of $CaCO_{3}$ be S moles per litre.

For that first we have to calculate the $K_{sp}$ , the formula for which is

$K_{sp}=[Ca^{2+}][CO_{3} ^{2-}]$

$S=\sqrt{K_{sp} }=\sqrt{(9.3)(10^{-8} )}=0.000304 mole/litre$

Now, the solubility in gram/litre is calculated to be

= mole/litre × molecular weight of $CaCO_{3}$

= 0.000304 × 100

= 0.0304 gram/litre

Hence, the solubility of chalk in gram/litre is calculated to be 0.0304.