Question

Exactly 5.00 l of air at -5.00 c is warmed to 100.0 c what is the new volume if the pressure remains constant

Answer 1

Given

$T_1$ = Initial temperature = $-5^{\circ}\text{C}+273.15=268.15\ \text{K}$

$V_1$ = Initial volume of air = 5 L

$T_2$ = Final temperature = $100^{\circ}\text{C}+273.15=373.15\ \text{K}$

To find

New volume of air when pressure is constant

Solution

$V_2$ = Final volume of air

From Charles' law we have

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\Rightarrow V_2=\dfrac{V_1T_2}{T_1}\\\Rightarrow V_2=\dfrac{5\times 373.15}{268.15}\\\Rightarrow V_2=6.96\ \text{L}$

The new volume of air is $6.96\ \text{L}$.