Question

exactly seven years ago, sam was 5 times the age of Janet. exactly 2 years ago, sam was 3 times the age of janet. what is the sum of their ages today

Answer 1

let Sam age be s, Janet be j

s-7 = 5(j-7)=5j-35

s-2 =3(j-2) =3j-6

solving for both

-5 = 2j-29

2j = 24

j = 12

s= 32

s+j = 44