Question

examine if 3, 7, 8, 17 are in proportion​

Answer 1

"We have, 4:6

=

6

4

=

(6÷2)

(4÷2)

[∵HCF of 4 and 6 is 2]

=

3

2

And 8:12

=

12

8

=

(12÷4)

(8÷4)

[∵HCF of 8 and 12 is 4]

=

3

2

∴4:6=8:12

Hence, 4,6,8,12 are in proportion."

Answer 2

Answer:

SOLUTION:

i) 15,45,40,120

we have 15,45,40,120

ratio of 15 to 45=\frac{15}{45}=\frac{15\div15}{45\div15}=\frac{1}{3}=1:3

[HCF OF 40 and 15, 45 is 15]

ratio of 40 to 120=\frac{40}{120}=\frac{40\div40}{120\div40}=\frac{1}{3}=1:3

[HCF of 40 and 120 is 40]

here, 15:4=40:120=1:3

ii) 33, 121,9,96

we have 33,121,9,96

ratio of 33 to121 = \frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}

ratio of 9 and 96= \frac{9}{96}=\frac{9\div3}{96\div3}=\frac{3}{32}

[HCF of 9 and 96 is 3]

here, 3:11\ne3:32

i.e\ 33:121\ne9:96

therefore, 31,121,9 and 96 are not in proportion.

iii) 24,28,36,48

ratio of 24 and 28 is \frac{24}{28}=\frac{24\div4}{28\div4}=\frac{6}{7}=6:7

[HCF of 36 and 48 is 12]

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Explanation:

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