Chemistry, asked by jerrinreji4, 9 months ago

Examine the oxidizing and reducing agent
(a) 4NH2+5O2-----> 4NO+6H2O
(b) H2O+F -------> HF+HOF
(c) Fe2O2+3CO -------> 2Fe+3CO2
(d) 2H2+O2 ---------> 2H2O

Answers

Answered by PixleyPanda
1

Answer:

Explanation:

a) The oxidation state of Oxygen is reduced, from 0 to -1. So Ammonia is reducing agent. Nitrogen and hhydrogen are oxidized to a state of +2 and +1 respectively.

b) Flourine is reduced to floride ion.. oxidation state of -1.

Water is the reducing agent..

c) Iron is reduced from an oxidation state of +3 to 0.. Carbon is oxidized from +2 state to +4. so carbon monozide is reducing agent.

d) Oxygen is reduced from a state of 0 to -2... hydrogen is oxidized. so hydrogen is the reducing agent.

Hope it helps

:)

Answered by savir2315
1

(a) NH3 is a reducing agent.

(b) H2O is a reducing agent.

(c) CO is a reducing agent.

(d) H2 is a reducing agent

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