Examine the oxidizing and reducing agent
(a) 4NH2+5O2-----> 4NO+6H2O
(b) H2O+F -------> HF+HOF
(c) Fe2O2+3CO -------> 2Fe+3CO2
(d) 2H2+O2 ---------> 2H2O
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Answer:
Explanation:
a) The oxidation state of Oxygen is reduced, from 0 to -1. So Ammonia is reducing agent. Nitrogen and hhydrogen are oxidized to a state of +2 and +1 respectively.
b) Flourine is reduced to floride ion.. oxidation state of -1.
Water is the reducing agent..
c) Iron is reduced from an oxidation state of +3 to 0.. Carbon is oxidized from +2 state to +4. so carbon monozide is reducing agent.
d) Oxygen is reduced from a state of 0 to -2... hydrogen is oxidized. so hydrogen is the reducing agent.
Hope it helps
:)
Answered by
1
(a) NH3 is a reducing agent.
(b) H2O is a reducing agent.
(c) CO is a reducing agent.
(d) H2 is a reducing agent
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