Examine whether (x-1) is a factor of 20²³ + x² +1.
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To examine whether x-1 is the factor of the polynomial
p(x) = 4x³ + 3x² - 4x - 3
We will use the factor theorem,
According to the theorem , the remainder should be 0 , only then the the given expression will be the factor of p(x)
x - 1 = 0 , so , x = 1
P(1) = 4(1)³ + 3(1)² - 4(1) - 3
P(1) = 4 + 3 -4 - 3 = 0
Thus,
The x - 1 is the factor of polynomial 4x³ + 3x² – 4x – 3
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