Example 1.35. Iron has body centred cubic lattice
structure. The edge length of the unit cell is found to be 286 pm.
What is the radius of an iron atom?
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Answer:
r = 123.7 pm
Explanation:
For BCC
radius = √3 edge length / 4
r = √3 a / 4
r = √3 * 286 / 4
r = 123.7 pm
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