the mean of 200 items is 48 and s.d is 3. the sum of squares of all items is
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- The sum of square of all items is = 462600
Given-
- Total items is (n) = 200
- Mean of total items (x bar) = 48
- Standard deviation (s) = 3
∑x = n x bar = 200 (48) = 9600
Also, we know that
σ² = 1/n ∑ x² - (x bar)²
3² = 1/200 ∑ x² - (48)²
1/200 ∑ x² = 2304 + 9 = 2313
∑ x² = 2313 × 200 = 462600
Hence the sum of squares of all items is 462600
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