EXAMPLE 1 Evaluate V-5 + 12i
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Assumption
√-5 + 12i = (x + iy) ..... (1)
(-5 + 12i) = (x + iy)²
(-5 + 12i) = (x² - y²) + i(2xy) .... (2)
Here
(x² - y²) = -5
2xy = 12
(x + y)² = √{(x² - y²)² + 4x²y²}
= √(25 + 144)
= √169
= 13
Hence,
(x² - y²) = -5 .... (3)
Also,
(x² + y²) = 13 ..... (4)
x² = 4
x = √4
x = 2
Also,
y² = 9
y = √9
y = 3
Here
xy > 0
Therefore,
(x = 2 and y = 3) or (x = -2 and y = -3)
Hence,
√-5 + 12i = (2 + 3i) or (-2 - 3i)
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