Question

Example 1: How much heat energy is necessary to raise the temperature of 5 kg of water from 20 °C to 100 °C 11​

Answer 1

Once you have all that, this is the equation:

Q=m×c×ΔT

(Q is usually used to symbolize that heat required in a case like this.)

For water, the value of c is 4.186Jg°C

So, Q=750×4.186×85=266858J=266.858kJ

The mass of the material, m.

The temperature change that occurs, ΔT.

The specific heat capacity of the material, c (which you can look up). ...

Here is a source of values of c for different substances:

Q=m×c×ΔT.

now we have ...

5 kg of water = 5000g..

temperature difference = 100 ⁰C- 20⁰C = 80 ⁰c.

C= FOR WATER IS EQUALL TO 4.186Jg⁰C

all you need to do essentially multiply specfic heat capacity with two valves above

the magnitude of heat in joules = m×c× T

= 4.186j/g ⁰C × 5000g× 80 ⁰C = 1,674,400 jules

your answer is 1 6 74 400 joules of energy required..

you can also convert into kilograms by dividing 1000 and also it converts into mega joules by dividing again.....

wish you all the best ☑✅✅✅

Answer 2

YOUR ANSWER IS HERE..

in the pictures.

I HOPE THIS WILL HELP YOU...