Question

Example 1 : Mahendra and Virat are sitting
at a distance 2 metre from each other. Their
masses are 50 kg and 60 kg respectively.
What is the gravitational force between them?​

Answer 1

$\sf\red{Answer:-}$

$\sf So\: force \: acting \: between \: them \: is = 5.0025\times 10^{-8} N$

$\sf\red{ Given :-}$

$\sf Mass \: of \: Mahendra (m_1) = 50kg$

$\sf Mass\: of\: Virat (m_2) = 60kg$

$\sf Distance \: between\: them\: is \:2m$

$\sf r= 2m$

$\sf\red {To\: find:-}$

$\sf Gravitational \: force$

$\sf\red{Solution :-}$

$\sf As \: we\: know\: that ,$

$\sf F=\dfrac{Gm_1m_2}{r^2}$

$\sf where,$

$\sf G = 6.67 \times 10^{-11} [gravitational\: constant]$

$\sf m_1 , m_2 = masses\: of\: the\: bodies$

$\sf r= distance \:b/w\: them$

$\sf Substituting \: the\: values ,$

$\sf F = \cfrac{6.67\times 10^{-11}\times 50\times 60}{2^2}$

$\sf F = \cfrac{6.67\times 10^{-11}\times 50\times 60}{4}$

$\sf F = 6.67\times 10^{-11}\times 50\times 15$

$\sf F = 6.67\times 10^{-11}\times 750$

$\sf F = 6.67\times 10^{-11}\times 75 \times 10$

$\sf F = 6.67\ \times 75\times 10^{-11}\times 10^1$

$\sf F = 500.25 \times 10^{-11+1}$

$\sf F = 500.25 \times 10^{-10}$

$\sf F = 50025\times 10^{-2} \times 10^{-10}$

$\sf F = 50025\times 10^{-2-10}$

$\sf{ F = 50025\times 10^{-12}N}$

or

$\sf{F = 5.0025× 10^{-8}N}$

$\sf \red{So\: force \: acting \: between \: them \: is = 5.0025\times 10^{-8} N}$

$\sf\red{Know\: more\: similar\:question\: in \: brainly:-}$

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