Question

Example 10.3 An object is thrown
vertically upwards and rises to a height
of 10 m. Calculate (i) the velocity with
which the object was thrown upwards
and (ii) the time taken by the object to
reach the highest point.
Solution:​

Answer 1

Answer:

Explanation:At the maximum height, v is 0.

From third law of kinematics,

v^2=u^2+2gh

Note that that g will be negative because it is not in the direction of displacement

Substituting values,

0=u^2- 2*10*10

u^2=200

u=14.14

For time taken to reach, use first equation of kinematics;

v=u+at

0=14.14-10t

t=1.414 sec

Thanks!!(Hope it helps)