Math, asked by kumkumrani9546, 5 months ago

Example 10. Through a rectangular field of length 90 m and breadth 60 m, two cross roads are
constructed which are parallel to the sides and cut each other at right angles through the
centre of the field. If the width of each road is 3 m, find
the area covered by the roads​

Answers

Answered by farhaanaarif84
0

Answer:

R.E.F. Image.

Given length of field = 90 m

width of field = 60 m.

Area of field =90×60

Area =5400m

2

length of road GEFH = 90 m.

length of road ABCD = 60 m.

width of each road = 3m [Given].

Area of roads =ar(ABCD)+ar.(GEFH)−ar(LIJK)

=90×3+60×3−3×3

=270+180−9

Area of roads =441m

2

.

∴ Area covered by roads =441m

2

.

cost of construction of roads =441×10

Total cost =4410Rs.

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