Question

Example 12. Given 1176 = 2^p.3^q.7^r, find
(i) the numerical values of p, q and r​

Answer 1

Step-by-step explanation:

Prime Factories 1176

1176=2*2*2*3*7*7=2^3*3^1*7^2

So p=3, q=1,r=2