Question

Example 2.4. Charge q is placed uniformly
over a loop of radius R. Find the electric field
intensity at a point at distance x from the centre,
on the axis of the loop.​

Answer 1

Answer:

Initially the field at the center is zero, i.e., field due to all the elements of the circular wire cancel each other.

field at the center after removing "x" length of wire = field at center due to "x" length of wire

=

4πϵ

o

1

q

x

R

2

=

4πϵ

o

1

2πRR

2

qx

(∵q

x

=

2πR

qx

)

=

8πϵ

o

R

3

qx

Explanation:

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