Question

EXAMPLE 2 A swimming pool is filled with three pipes with uniform flow. The first two pipes
operating simultaneously, fill the pool in the same time during which the pool is filled by the third
pipe alone. The second pipe fills the pool five hours faster than the first pipe and four hours slower
than the third pipe. Find the time required by each pipe to fill the pool separately.​

Answer 1

Answer:

Let V be the volume of the pool and x the number of hours required by the second pipe alone to fill the pool. Then, the first pipe takes (x+5) hours, while the third pipe takes (x−4) hours to fill the pool. So, the parts of the pool filled by the first, second and third pipes in one hour are respectively

x+5V,xV,x−4V

Let the time taken by the first and second pipes to fill the pool simultaneously be t hours.

Then, the third pipe also takes the same time to fill the pool

∴(x+5V+xV)t= Volume of the pool

Also, x−4Vt= Volume of the pool

⇒(x+5V+xV)t=x−4Vt⇒x+51+x1=x−41

⇒(2x+5)(x−4)=x2+5x⇒x2−8x−20=0⇒x2−10x+2x−20=0⇒(x−10)(x+2)=0

⇒x

Step-by-step explanation:

I think it is helpful

Answer 2

Answer:

Here your answer :

there 3 pictures I have mark like 1 , 2 , 3

from pg 1 our answer start

ok

Please mark me as BRAINLIST , FOLLOW ME AND THANK ME

Bye bye ok