Science, asked by anjalistanynadar542, 9 months ago


Example 2: An aeroplane taxies on the runway for 30 s with an acceleration of 3.2 m/s?
before taking off. How much distance would it have covered on the runway? with full answer​

Answers

Answered by nakulathul
6

Answer:brainliest pls

Time(t) = 30 s. s = 1440 m. Total distance covered (s) = 1440 metres.

Explanation:

Initial speed of airplane  u=0 m/s

Acceleration of the plane  a=3.2 m/s  

2

 and time taken t=3.28 s

Using formula, distance covered S=ut+  

2

1

​  

at  

2

   

⇒   S=0(32.8)+0.5(3.2)(32.8)  

2

=1721.3∼1720m

Answered by Anonymous
3

Answer:

The aeroplane would have covered 1440 m distance.

Explanation:

a = 3.2 m/s²

t = 30 s

u = 0 m/s

s = ut + ½ at²

=> s = 0 * 30 + ½ * 3.2 * 30²

=> s = 0 + ½ * 3.2 * 900

=> s = ½ * 900 * 3.2

=> s = 450 * 3.2

=> s = 1440 m

The aeroplane would have covered 1440 m distance.

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