Question

solve this logrithim​

Answer 1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

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Answer 2

there is a formula a^loga(b) =b  

let log2(x)=y  

9^[log3(y)]=-y^2+y+1  

3^[2log3(y)]=-y^2+y+1  

{3^[log3(y)]}^2=-y^2+y+1  

now using the formula a^loga(b) =b  

y^2=-y^2+y+1  

0=-2y^2+y+1  

0=2y^2-y-1  

0=(y-1)(2y+1)  

y=1,-1/2  

then subbing log2(x)=y  

log2(x)=1  

2^1=x  

x=2  

log2(x)=-1/2  

2^(-1/2)=x  

x=2,2^(-1/2)

Hope this helps you.....