Question

The number of ways of arranging 6 red roses and 3 yellow roses of different sizes into a garland so that no two yellow roses are together is

Answer 1

total ways of arranging is 6red roses+3yellow roses=9!

In the given condition we assume 2 yellow roses that are not together is taken as 1

and from that we could find that 6+1=7!

7!=7x6x5x4x3x2x1=5040

so 5040x2=10080