Question

Example 2. Find the area of a rectangle whose length is
8 m and diagonal 10 m.​

Answer 1

Answer:

Answer

In the figure, rectangle ABCD has

Breadth =BC=AD=8 cm

Diagonal BD=17 cm

Let the length =AB=CD=x cm

Now, triangle DAB is a right-angle triangle.

So, from Pythagorus theorem,

AB

2

+AD

2

=BD

2

x

2

+8

2

=17

2

x

2

=289−64

x

2

=225

x=

225

x=15 cm

Now, area of the rectangle =length×breadth

=15×8

=120 cm

2

and perimeter =15+15+8+8=46 cm

solution

Answer 2

Answer:

80m

Step-by-step explanation:

area of rectangle = l×b

= 8×10

= 80m