Question

Example 2. From the position-time graph given,
find the
(a) Average speed
(b) the distance travelled between 2 sec and 5
sec​

Answer 1

40m

Since the velocity always increases, the distance traveled will be equal to the displacement of the object between the time.

Since, displacement = area under the curve for the graph

Area of trapezium =

2

1

(sum of parallel sides)(distance b/w parallel sides)

Hence,

d =

2

1

(11.25+15)(4) =40 m