Question

Example 2 : Show that the diagonals of a rhombus are perpendicular to each other
Therefore, each of the angles of a rectangle
a
S
A
Solution : Consider the rhombus ABCD (see Fig. 8.13).
You know that AB = BC = CD = DA (Why?)
Now, in A AOD and A COD.
C
N
S
OA = OC (Diagonals of a parallelogram
bisect each other
OD = OD
(Common)
o
AD = CD
А
B
Fig. 8.13
Therefore, A AOD = A COD
(SSS congruence rule)
This gives, 2 AOD = 2 COD (CPCT)
But, ZAOD + 2 COD = 180° (Linear pair)
So, 22 AOD = 180°
or,
ZAOD = 90°
So, the diagonals of a rhombus are perpendicular to​

Answer 1

Answer:

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