Example 21: A constant force of 50 N is applied to a 20 kg block for 10 seconds. (a) what is the final speed of the block if it was originally
moving at a speed of 15 m/s ?
F = 50N
20 kg
Answers
Answered by
1
Answer:
40m/s
Explanation:
DATA:
F = 50N
M=20 KG
t= 10s
vi=15m/s
formula
F=ma
50=20 (a)
50÷20=a
2.5m/s^2
formula
vf=vi+at
vf=15+2.5×10
vf=40m/s
Answered by
1
Answer:
answer will be vf=
Explanation:
40 m/
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