Question

Example 23. In the given figure, m and n are two plane mirrors parallelt
each other. Prove that incident ray CA is parallel to reflected ray BD. how to solve this??​

Answer 1

Hi mate here is the answer:-✍️✍️

${} \huge \mathfrak \pink{solution > }$

Given:

m and n are parallel to each other.

To prove:

ray BD || ray CA.

Proof:

BQ is the normal to the reflecting surface.

⇒ BQ ⊥ n.Similarly, AP is the normal to the reflecting surface.

⇒ AP⊥ m.

⇒ Since m || n.AP || BQ.

⇒ ∠QBA = ∠BAP (Alternate angles are equal)

∴ 2∠QBA = 2∠BAP

∠DBA = ∠BAC

(The angle of incidence = The angle of reflection)ray BD || ray CA ( Alternate angles are equal ).

Hope it helps you ❣️☑️☑️