Math, asked by Abhishekpatil6811, 11 months ago

Example 3. A dealer mixes tea costing * 6.92 per kg, with tea costing 7.77 per kg and sells themixture at * 8.80 per kg and earns a profit of 17 1/2% on his sale price. In what proportion doeshe mix them?​

Answers

Answered by aviratwalia18
5

Answer: there are two methods to this answer, pls mark as brainliest

Step-by-step explanation:

Method 1

6.92x + 7.77y =

82.5

100

82.5

100

×8.80(x+y)

6.92x + 7.77y = 7.26x + 7.26y

0.34x = 0.51y

x/y = 0.51/0.34 = 51/34 = 3/2

x:y = 3:2

Method 2

1 kg mixture is sold at Rs. 8.8 and there is a profit of 17.5 % on the sale price.

i.e., Profit in selling 1 kg mixture =

8.8

×

17.5

100

8.8

×

17.5

100

= 1.54

Cost Price of 1 Kg mixture = 8.8 - 1.54 = Rs.7.26

Applying rule of alligation

Unit price

of tea 1

6.92 Unit price

of tea 2

7.77

Unit price of the mixture

7.26

7.77-7.26=0.51

7.26- 6.92=0.34

Required ratio = = 0.51 : 0.34 = 51 : 34 = 3 : 2

it is important to note the statement "profit of 17 .5 % on sale price".i.e., the trader gains profit of 17.5% on selling price and not on cost price. if question was mentioning "profit was 17.5%", then answer would have been different.

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