Question

Example 3 : Find K. if the slope of a line passing through the points (3.-5) and (K,-1)is 1/3​

Answer 1

Answer:

K=15

Step-by-step explanation:

slope of a line = y2-y1/x2-x1

1/3 = -1-(-5)/k-3

k-3=12

k= 15

HOPE THIS HELPS

Answer 2

Given,

A line is passing through the points (3,-5), and (K,-1) has a slope of 1/3.

To find,

Find the value of K.

Solution,

• Suppose, a line has end points (x1,y1) and (x2,y2) then the slope (m) of the line can be calculated by -

       m = (y2-y1)/(x2-x1)

• Here y2 = -1,  y1 = -5,  x2 = K,  x1  = 3.

Putting these values in the formula for slope (m) of the line-

⇒   m = $\frac{-1-(-5)}{K-3}$  

⇒   m = $\frac{4}{K-3}$

⇒   The value of slope (m)  is given 1/3.

Therefore,

        $\frac{1}{3}$ = $\frac{-1-(-5)}{K-3}$

• In the next step, after cross multiplying we will  get:

⇒   1(K-3) = 3(4)

⇒   K - 3 = 12

⇒   K = 15

Hence, if the slope of a line passing through the points (3.-5) and (K,-1)is 1/3​, then the value of K = 15.